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  <title>Regular Tetradedron: Net, bond angle, methane</title>
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<a href="http://www.mathsisfun.com/platonic_solids.html"><img
src="../../images/tetrahedron.jpg" alt="Regular Tetrahedron" width="175"
height="122" class="float_left" /></a><p>A <span
class="colored_green_bold">regular tetrahedron</span> is a 3D figure that has
four congruent triangular faces.</p>

<p>You can make a regular tetrahedron (like the one pictured) by printing the
tetrahedron net found at</p>

<p><a
href="http://www.mathsisfun.com/geometry/tetrahedron-model.html">http://www.mathsisfun.com/geometry/tetrahedron-model.html</a>
</p>

<p>Note: you may have to reduce the size of your print to get the net to fit on
one page. 90% works well for me.</p>
<hr />

<p><a
href="http://www.creative-chemistry.org.uk/molecules/tetrahedral.htm"><img
src="../../images/methane_tetrahedral_bond_angle.jpg"
alt="Methane atoms form a tetrahedral structure" width="200" height="125"
class="float_right" /></a>The atoms in <span class="colored_violet_Bold">a
molecule of methane</span> <math xmlns="http://www.w3.org/1998/Math/MathML">
  <msub>
    <mi>CH</mi>
    <mn>4</mn>
  </msub>
</math>are arranged in a tetrahedral pattern where the carbon atom is at the
center of the tetrahedron and each hydrogen atom occupies a corner of the
tetrahedron.</p>

<p>Use the following figure to <span class="colored_red_bold">calculate the
angle between any two hydrogen atoms</span> relative to the center of the
carbon atom.</p>

<p><a
href="http://mathcentral.uregina.ca/QQ/database/QQ.09.00/nishi1.html"><img
alt="Regular tetrahedron inscribed inside a cube" src="../../images/nishi1.gif"
width="530" height="227" /></a></p>

<p>The side length of the cube is 1. Thus
<math xmlns="http://www.w3.org/1998/Math/MathML">
  <mover>
    <mi>PT</mi>
    <mo>¯</mo>
  </mover>
  <mo>=</mo>
  <mn>1</mn>
</math> </p>

<p>Use the Pythagorean formula to compute the length of
<math xmlns="http://www.w3.org/1998/Math/MathML">
  <mover>
    <mi>QP</mi>
    <mo>¯</mo>
  </mover>
</math>. Thus <math xmlns="http://www.w3.org/1998/Math/MathML">
  <mover>
    <mi>QP</mi>
    <mo>¯</mo>
  </mover>
  <mo>=</mo>
  <msqrt>
    <msup>
      <mn>1</mn>
      <mn>2</mn>
    </msup>
    <mo>+</mo>
    <msup>
      <mn>1</mn>
      <mn>2</mn>
    </msup>
  </msqrt>
  <mo>=</mo>
  <msqrt>
    <mn>2</mn>
  </msqrt>
</math> </p>

<p>R is a point exactly halfway between points Q and P. Thus
<math xmlns="http://www.w3.org/1998/Math/MathML">
  <mover>
    <mi>RP</mi>
    <mo>¯</mo>
  </mover>
  <mo>=</mo>
  <mfrac>
    <msqrt>
      <mn>2</mn>
    </msqrt>
    <mn>2</mn>
  </mfrac>
</math> and <math xmlns="http://www.w3.org/1998/Math/MathML">
  <mover>
    <mi>RO</mi>
    <mo>¯</mo>
  </mover>
  <mo>=</mo>
  <mfrac>
    <mn>1</mn>
    <mn>2</mn>
  </mfrac>
</math></p>

<p>The tangent of angle<math xmlns="http://www.w3.org/1998/Math/MathML">
  <mo>&#x2220;</mo>
  <mi>ROP</mi>
</math> is the ratio of sides <math xmlns="http://www.w3.org/1998/Math/MathML">
  <mover>
    <mi>RP</mi>
    <mo>¯</mo>
  </mover>
</math>and <math xmlns="http://www.w3.org/1998/Math/MathML">
  <mover>
    <mi>RO</mi>
    <mo>¯</mo>
  </mover>
</math>. Thus <math xmlns="http://www.w3.org/1998/Math/MathML">
  <mrow>
    <mi>arctan</mi>
    <mo>&#x2061;</mo>
    <mrow>
      <mo>(</mo>
      <mrow>
        <mfrac>
          <mfrac>
            <msqrt>
              <mn>2</mn>
            </msqrt>
            <mn>2</mn>
          </mfrac>
          <mfrac>
            <mn>1</mn>
            <mn>2</mn>
          </mfrac>
        </mfrac>
      </mrow>
      <mo>)</mo>
    </mrow>
    <mo>=</mo>
    <mrow>
      <mi>arctan</mi>
      <mo>&#x2061;</mo>
      <mrow>
        <msqrt>
          <mn>2</mn>
        </msqrt>
        <mo>=</mo>
        <mn>54.73561032</mn>
        <mo>°</mo>
      </mrow>
    </mrow>
  </mrow>
</math> </p>

<p>Since hydrogen atoms occupy the locations at points Q and P, the angle
<math xmlns="http://www.w3.org/1998/Math/MathML">
  <mo>&#x2220;</mo>
  <mi>QOP</mi>
  <mo>=</mo>
  <mrow>
    <mn>2</mn>
    <mo>×</mo>
    <mrow>
      <mo>&#x2220;</mo>
      <mi>ROP</mi>
    </mrow>
  </mrow>
  <mo>=</mo>
  <mn>109.5</mn>
  <mo>°</mo>
</math> </p>

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<hr />

<p>The end</p>
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